I believe the answer must be 227/732 because we need probability of "1" in selected number.. so, we must consider total number of numbers which contain "1"..
So,
0 - 99 ==> _ _ ==> 10 + 10 = 20
100 - 200 ==> _ _ _ ==> 100 + 10 + 10 = 120
201 - 300 ==> _ _ _ ==> 0 + 10 + 10
301 - 400 ==> _ _ _ ==> 0 + 10 + 10
401 - 500 ==> _ _ _ ==> 0 + 10 + 10
501 - 600 ==> _ _ _ ==> 0 + 10 + 10
601 - 700 ==> _ _ _ ==> 0 + 10 + 10
701 - 732 ==> _ _ _ ==> _ + 10 + 4
Occurrence of _11 = 7 (11,211,311,411,511,611,711)
Occurrence of 1_1 = 9 (101,121,131,141,151,161,171,181,191)
Occurrence of 11_ = 9 (110,112,113......119)
occurrence of 111 = 1 (we need to do -2)
So, 254 - 7 - 9 - 9 -2 = 227
227/732
R A H U L