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Suits problem

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Suits problem

by oks » Wed May 13, 2009 5:11 pm
X percents of the rooms are suits, and Y Percents of the rooms are painted light blue?
Which of the following best represents the least Percentage of the light blue painted suits?
(a) X-Y.
(b) Y-X + 100.
(c) 100X-Y.
(d) X+Y-100.
(e) 100-XY.

OA: D

Pls explain. Thanks!
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by DeepakR » Wed May 13, 2009 6:17 pm
n(XUY)=n(X)+n(Y) - n(X intersection Y)

We need to find the least value of n(X intersection Y) = n(X)+n(Y) - n(XUY)
to get the least value of X intersection Y the XUY should be maximum in that case there will be only 2 types of rooms and hence XUY=100

So least percentage = X + Y - 100 = E.)

- Deepak
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