BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

permutation and combination dose for the day

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

by ajith » Wed Feb 24, 2010 12:34 am
thephoenix wrote:Five cards are to be selected from 10 cards numbered 1 to 10. In how many ways can the cards be selected so that the average of the five numbers selected is greater than their median?

(A) 111
(B) 116
(C) 222
(D) 232
(E) 252
I searched on the web and found out that one approach to solve this is

1. Find the no of ways in which one can select 5 cards from 10
2. Find the no of ways in which one can select 5 cards such that the mean of the numbers = median of the numbers
3. Find the no of ways in which mean not equal to median
4. By symmetry half of these should have mean> median and half will have mean <median

Which yields an answer of A

Anybody has any better approach?
Always borrow money from a pessimist, he doesn't expect to be paid back.
Top
Post new topic Post Reply
• Page 1 of 1