BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

help required

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 69
Joined: Sat Jan 23, 2010 1:14 pm
by swapna » Sat Jan 23, 2010 8:30 pm
In a certain game, a large container is filled with red,yellow,green and blue beads worth,respectively,7,5,3 and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147000, how many red beads were removed?
5
4
3
2
0

Answer is D. This is from the official guide 11th edition. Any value can be gvn to r and still by manipulating the value of y,g and b answer can be obtained as 147000.Can some explain??
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Wed Jan 13, 2010 2:10 am
Thanked: 1 times

by chaitanya.sonavale » Sun Jan 24, 2010 2:04 am
Hi,

147000 = 147 * 10 * 10 * 10 = (7 * 7 * 3) * (5*2) * (5*2) * (5*2)

but r = 7, y = 5, g = 3 , b = 2

Hence 2 red, 3 yellow, 1 green and 3 blue were removed
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 57
Joined: Fri Jan 22, 2010 11:25 am

by bedazzled » Sun Jan 24, 2010 7:35 am
What if we try to do in this way


147000 = 35 * 21 * 20 * 10
= (7*5) * (3 * 7) * (5*4 ) * (2*5)

here we get red =5 , yellow=7, green=4, blue=5.

We get red=5 which is indeed an answer.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Wed Jan 13, 2010 2:10 am
Thanked: 1 times

by chaitanya.sonavale » Sun Jan 24, 2010 7:59 am
7,5,3,2 are values assigned to red,yellow,green and blue beads respectively. So we are trying to find how many beads of each color are used. In other words, trying find the prime factors of 147000 and comparing them to given values to get the answer.

e.g. we get 7 twice and 7 is value of red beads. Hence there have to be 2 red beads.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 57
Joined: Fri Jan 22, 2010 11:25 am

by bedazzled » Sun Jan 24, 2010 8:45 am
I think I missed the essence of question. Thanks Chaitanya.

we have to consider here the no. the time that value is occurring like 7 occurred 2 times hence red=2 not the product value of it.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1022
Joined: Mon Jul 20, 2009 11:49 pmFollowed by: 2 members
Location: Gandhinagar
Thanked: 41 times

by shashank.ism » Fri Feb 19, 2010 6:05 am
This question is really tricky ,....factorizing is the main concept in this problem...
My Websites:
www.mba.webmaggu.com - India's social Network for MBA Aspirants

www.deal.webmaggu.com -India's online discount, coupon, free stuff informer.

www.dictionary.webmaggu.com - A compact free online dictionary with images.

Nothing is Impossible, even Impossible says I'm possible.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Senior | Next Rank: 100 Posts
Posts: 85
Joined: Sat Jan 30, 2010 3:49 am
Location: Hyderbad, India
GMAT Score:660

by abhi.genx7 » Fri Feb 19, 2010 12:37 pm
This is the method i tried , could be useful.
I looked for 147 . that is 3 less than 150. so 49*3 so two 7's are used.
The rest are 5*2=10.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1022
Joined: Mon Jul 20, 2009 11:49 pmFollowed by: 2 members
Location: Gandhinagar
Thanked: 41 times

by shashank.ism » Sat Feb 20, 2010 12:38 am
abhi.genx7 wrote:This is the method i tried , could be useful.
I looked for 147 . that is 3 less than 150. so 49*3 so two 7's are used.
The rest are 5*2=10.


thats a nice approach..abhi.genx
My Websites:
www.mba.webmaggu.com - India's social Network for MBA Aspirants

www.deal.webmaggu.com -India's online discount, coupon, free stuff informer.

www.dictionary.webmaggu.com - A compact free online dictionary with images.

Nothing is Impossible, even Impossible says I'm possible.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1