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Mean Vs Median

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Source: — Data Sufficiency |
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by rijul007 » Wed Jan 04, 2012 9:59 pm
karthikpandian19 wrote:Set T contains more than one element. Is the median of set T greater than its mean?
(1) Set S has positive range.
(2) The elements of the set are not consecutive integers
(1) Set S has positive range.
Clearly insufficient


(2) The elements of the set are not consecutive integers
Mean and median for {2,4,6,8,10} are the same
Mean and media for {1.7.10.103} are not the same
insufficient

Combining two statements
Still insufficient
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by karthikpandian19 » Thu Jan 05, 2012 9:07 pm
OA is E
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by Anurag@Gurome » Fri Jan 06, 2012 5:44 am
karthikpandian19 wrote:Set T contains more than one element. Is the median of set T greater than its mean?
(1) Set S has positive range.
(2) The elements of the set are not consecutive integers
(1) Set T has a positive range means T can have any range of numbers from 1 till infinity; NOT sufficient.

(2) The elements of the set are not consecutive integers implies it could be any range of numbers from 1 till infinity; NOT sufficient.

Combining (1) and (2), again is NOT sufficient to find if the median of set T is greater than its mean.

The correct answer is E.
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by ArunangsuSahu » Fri Jan 06, 2012 8:40 am
Let's give a simpler explanation

Remember 1 thing: If the median is closer to the smaller value/values mean will be greater than the median and median is closer to the bigger values median will be greater than


Statement 1:

Range is +ive
S= {0,5}--mean = median
S= {0,1,5}--median<mean
S= {0,3,5}--median>mean

So INSUFFICIENT

Statement 2:
Elements are not consecutive

S= {5,5}--mean = median
S= {1,3,6}--mean >median
S= {1,5,7}--median > mean

INSUFFICIENT

Combining also ..INSUFFICIENT

(E) is the answer
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