Group 5^23 with 2^ 23 which is then 10^23.
10^23 is 1 followed by 23 zeros.
The remaining 5 then makes this 5 and 23 zeros.
Multiplied by 7 is 35 and 23 zeros.
Multiplied by 49 is some number greater than 1000 but less than 10000, not important what it is, but has 4 digits.
4 digits plus 23 zeros is 27
How many digits are there in the product \(2^{23}\cdot 5^{24}\cdot 7^3?\)
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