Statement 1: n^2 = z, where z is an integer. So n = ±sqrt(z). Well, if z=2 then n is not an integer, while if z=1, n is an integer. Not sufficient.anaitalt wrote:(pg 290)
Is n an integer?
(1) n^2 is an integer
(2) n^(1/2) is an integer
Can anyone please give better reasoning than the OG?
Thanx
Statement 2: sqrt(n) = z, where z is an integer. So n = z^2, and n is the square of an integer, so must be an integer. Sufficient.
