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arithmetic mean

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by divya23 » Mon Jun 13, 2011 10:13 pm
during sale each shirt sold at 15 and sweatr for 25 ,did the store sell more sweater than shirts
a.mean of all prices of shirt and sweater is = 21
b.total price of all the shirt and sweater sold = 420

[spoiler]ans = a[/spoiler]
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Source: — Data Sufficiency |

by GMATGuruNY » Tue Jun 14, 2011 1:27 am
During a sale, a clothing store sold each shirt at a price of $15 and each sweater at a price of $25. Did the store sell more sweaters than shirts during the sale?

(1) The average (arithmetic mean) of the prices of all the shirts and sweaters that the store sold during the sale was $21.

(2) The total of the prices of all the shirts and sweaters that the store sold during the sale was $420
This is a weighted average question. Almost no math is needed.

Statement 1: Average of all sales = $21.
Since the average (21) is closer to the price of a sweater (25) than to the price of a shirt (15), the store sold more sweaters than shirts.
Sufficient.

Statement 2: Total of all sales = $420.
No way to determine whether the store sold more sweaters than shirts.

The correct answer is A.
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by amit2k9 » Thu Jun 16, 2011 9:15 pm
a using weighted average since 21 is closer to 25 hence it is sufficient.

allegation formula confirms this = (25-21)/(21-15) = 4/6 = 2/3 = sw/shirts.

b 3 shirts + 5 sweaters = 84

shirts = 84/3 = 28 possible with sweaters = 0
or sweaters = 15 giving 15*5 = 75

75 + 9 = 84 meaning sweaters = 3 sweaters. not sufficient.


Thus A it is.
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