When a graph intercepts X axis, Y = 0. Thus the question is asking what is the value of X in (x+a)(x+b) = 0
(x+a)(x+b) => x^2 + (a+b)x + ab = 0
now we need to know (a+b) & ab...

1. (a+b) = -1 gives value on one unknown.
2. This option simply states that when X = 0 Y = -6
so (0+a)(0+b) = -6 => ab = -6

knowing the value of two unknowns we can solve the original equal for the value of X
(x+2)(x-3) = 0, so X = -2 or 3....

So we know that the graph intersects X axis at two points -2 and 3 thus both statement together are sufficient

I dont see how it could be C. I think is it E.

Because with both statements we get that if y=0: x can be either 2 or -3.

1. From statement 1: we get 0=x^2+x+ab

2-. from statement 2 we get: -6=ab

3. Both statements together: 0=x^2+x-6 ...... x=either 2 or -3

Correct me if I am wrong

cris wrote:I dont see how it could be C. I think is it E.

Because with both statements we get that if y=0: x can be either 2 or -3.

1. From statement 1: we get 0=x^2+x+ab

2-. from statement 2 we get: -6=ab

3. Both statements together: 0=x^2+x-6 ...... x=either 2 or -3

Correct me if I am wrong

You can have two X-axis points when the equation is a parabola as seen here b/c y=x^2

Hi preciusrain7! thanks for your post. I knew that it is has two points because it is a parabola...what I menat is that the question asks "at what point (singular) does...", and we have 2 points...so we dont know which of the two select...

This is the way DS problems work no? if we are asked for 1 point and with the info given we can calculate more than 1 and we can not know which one they are asking us for...then is E.

Could any one clarify this for me please, thanks!

cris, I got ur point. But the Qs is asking -

at what point does the graph of y = (x+a)(x+b) intersects the x-axis?

. In this case, as it is a parabola, it is having two X-intercepts. So it is not giving any extra answer but a detailed answer u can say. Say - (X1,0) and (X2,0) - these are the two points where the graph intercepts the X-axis.
As a conclusion, we can draw that it dos not mean in every case where we are getting two answers does not mean that we are failing to get the correct answer (As it is here). Are you getting me, Cris?