BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

coordinate

Expert replies
Source: — Problem Solving |

by StarDust845 » Fri Jan 18, 2008 1:49 pm
Substitute the two points in the equation and solve.
Join the discussion

by II » Fri Jan 18, 2008 3:14 pm
ok ... we know that an equation of line is y=mx+c, where m is the gradient/slope and c is the y-intercept.

The question provide: X=3Y-7.
We need to firstly get this in the format of y=mx+c

so x=3y-7 can be rearranged:
x=3y-7
x+7=3y
(x+7)/3 = y

So y=1/3x + 7/3

we know can easily tell that the y-intercept is 7/3.
So we have one coordinate which fits the line equation. This coordinate is (0,7/3).

If we find the x-intercept, then we will have another coordinate to play with. So substitute a value of 0 for y in the equation:
0=1/3x + 7/3
-7/3=1/3x
-7/3*3/1=x
-21/3=x
x=-7.
So we have another coordinate (-7,0) which fits the equation.

This second coordinate is easier to work with ... so lets take this one forward:

The question mentions (a,b) and (a+3,b+K) being 2 points on the line.
So we have established that (-7,0) is one of these points.
So the 2nd point on the line is (-7+3,0+k) or (-4,0+k)

Lets substitute these values (x=-4, y=0+k) into the equation:

y=1/3x+7/3
0+k=1/3(-4)+7/3
k=-4/3+7/3
k=3/3
k=1

So the answer is D.

What is the official answer please ? And where is this question from ?

Thanks.
Join the discussion

by simplyjat » Fri Jan 18, 2008 8:25 pm
You do not need to do all the calculations to find (-7,0) and (0,7/3).

This question can be easily solved by algebra X = 3Y -7
a = 3b - 7
=> 3b - a = 7

and
(a+3) = 3(b+k) -7
=> a + 3 = 3b + 3k -7
=> 3 = (3b-a) + 3k -7
=> 3 = 7 + 3k -7
=> 3k = 3
=> k = 1
simplyjat
Join the discussion

by II » Sat Jan 19, 2008 1:33 am
Good point !
I had just been studying Geometry ... and all the geometry concepts were running through my mind.
Agree that it is quicker using algebra here ! Thanks.
Join the discussion

by sibbineni » Sun Jan 20, 2008 10:53 am
i think subtitution wont give correct ans all the times...

In the XY-coordinate system, if (a,b) and (a+3, b+ K) are two points on the line defined by the equation X=3Y-7, then K=

A) 9
B) 3
C) 7/3
D) 1
E) 1/3


write the equation x=3y-7 in the y=mx+c format and find ou the slope

y=1/3x+7


m=1/3 which is slope and then by using slope formula

m=y2-y1/x2-x1

substitute 2 points in the above formula and then equate the slope...

1/3=b+k-b/a+3-A

K=1. is the ans
Join the discussion