Discussion of some math questions from the GMAT Prep exam:

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
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I took the prep exam and got 700. However, I'm not sure how to do some of the questions and there are no

explanations, so I'm turning to the collective. This is also a good way for me to study by writing down the

troubling questions. I found that as I wrote down the questiosn below, I learnt how to do some of them.

1.
5^(21) x 4^(11) = 2x10^(n) what is n?

We know 5 x 4 is 20 or 2 x 10^(1).

I guessed the correct answer to be [spoiler]n = 21[/spoiler], but i'm not sure why. Anyone know?

2. - DS
are x and y both positive?
(1) 2x - 2y = 1
(2) x/y > 1

The answer is [spoiler]C (both needed)[/spoiler] but I think it should be E.
(1) : x - y = 1/2
(2): x & y both have to have the same sign. I'm not sure how to work it out to get C


3. - DS
if x and y are positive integers, what is the value of xy?
(1) the GCF (greatest common factor) of x and y is 10
(2) the LCM (least common multiple) of x and y is 180

the answer is C but I don't know how. I suck at the GCf/LCM questions.

4. -DS
In the xy-plane, what is the y-intercept of line l?
(1) the slope of line l is 3 times its y-intercept
(2) the x-intercept of line l is -1/3

y = mx + b, where m is slope and b is y-intercept
..so
(1): y = 3bx + b - doesn't help
(2): 0 = m(-1/3) + b, -b/m = -1/3 or b/m = 1/3 We know the ratio but not exact values

(1) & (2) cancels out the b, so I guess it tells us the same thing? Confused?

5. - DS
The sum of positive integers x and y is 77. What is value of xy?
(1) x = y + 1
(2) x and y have the same tens digit.

The answer is D but I incorrectly chose A. Not sure how they get D.
(1) thats easy to see why its sufficient.
y + 1 + y = 77 => 2y = 76, you know y and x.
(2) this just tells us that :
10s + t + 10s + r = 77 => 20s + t + r = 77
you don't know t or r, so can you find out the product of x and y?

6. - DS
Martha bought a chair and a table at an auction and sold both items at her store. Her gross profit from the

purchase and sale of the chair was what percent greater than her gross profit from the purchase and sale of the

table?
(1) Martha paid 10% more for the chair than for the table
(2) Martha sold the chair for 20% more than she sold the table.

profit for chair (p_c) = selling price of chair (s_c) - purchase price of chair (b_c)
profit for table (p_t) = selling price of table (s_t) - purchase price of table (b_t)

(1) b_c = 1.1(b_t)
(2) s_c = 1.2(s_t)

p_c = 1.2(s_t) - 1.1(b_t)
p_t = s_t - b_t

[spoiler]Ok I see why this can't be solved. I thought it was C, but now I know why its E. Thanks to writing it out.[/spoiler]

7. - DS
Of the 60 animals on a certain farm, 2/3 are either pigs or cows. How many animals are cows?
(1) the farm has more than twice as many cows as it has pigs
(2) the farm has more than 12 pigs

60 animals -> 2/3 (60), 40 animals that can be either pigs or cows
(1) c > 2p
40 = 2p + p => 40 = 3p
(2) p > 12

[spoiler]I thought the answer should be E since (1) and (2) are both inconclusive, however I am wrong. While writing this, I

just realized that if p > 12, than p could be 13, in which case c > 26. 13 + 27 = 40

so the answer is C. [/spoiler] I just wish I realized that while writing the test!!!

8. - DS
Are at least 10% of the people in the Country X who are 65yrs old or older employed?
(1) in country X, 11.3% of population is 65 years old or older
(2) in country X, of the population 65 years or older, 20% of the men and 10% of the women are employed.

[spoiler]Answer is B but I didn't get it originally (chose E). [/spoiler]

I think I do now... Let there be 100 people how are 65 or older and try different combinations of men and women...


As I wrote these down, I figured out how to get most of them. However, I still don't know how to do #1, #3, and #5.

Thanks

[/spoiler]
Source: — Quantitative Reasoning |

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by gmattic » Sat Jan 02, 2010 4:49 pm
Here's another one. I got it right but my initial approach was wrong, not sure why.

to furnish a room in a model home, an interior decorator is to select 2 chairs and 2 tables from a collection of chairs and tables in a warehouse that are all different from each other. If there are 5 chairs in a warehouse and if 150 different combinations are possible, how many tables are in the warehouse?

So my approach was the following:
- this is a combination question
-- two different combinations, choosing two chairs and choosing two tables

We know there are 150 combinations available and that there are 5 chairs to choose from. We need to know how many tables to choose from.

I did 150 = "5 choose 2" + "n choose 2"

5 choose 2 = 5!/(2!3!) = 10

150 = 10 + "n choose 2"
140 = "n choose 2"
240 = n(n-1) I couldn't solve this.

Then I thought how about:
150 = "5 choose 2" x "n choose 2" then:
150 = 10 x "n choose 2"
30 = n(n-1) = 6 x 5

The answer is 6, which is correct.

However I'm not sure why we should be multiplying instead of adding the two combinations. Anyone know?

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by MBAorBust » Sat Jan 02, 2010 8:42 pm
Q1:
5^21 * 4^11 = 2*10^n
Realize that 4^11 can be rewritten as (2^2)^11 or 2^22

5^21 * 2^22 = 2*10^n
Divide both sides by two

5^21 * 2^21 = 10^n

regroup since it is the same exponent

(5*2)^21 = 10^n

10^21 = 10^n

n=21

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by papgust » Sat Jan 02, 2010 8:45 pm
1. 5^21 * 4^11 = 2 * 10^n

5^21 * (2*2)^11 = 2 * (2*5)^n

5^21 * 2^11 * 2^11 = 2 * 2^n * 5^n

Equate powers with same base 5,
21=n


2. x and y positive?

A. 2(x-y) = 1
x-y = 1/2. Insufficient.

B. x/y > 1
or x > y
But you don't whether x is +ve,-ve or y is +ve,-ve. Insufficient.

Combined,
you know x > y from B. To satisfy x - y = 1/2, x and y have to be +ve. You could even try out some scenarios to confirm.
Sufficient. C
[I only noticed now that you got the method of prob #2 and you are struggling only with 1, 3 and 5 :). I'm heading across to 3 and 5 now].


3. xy?

A. 10 = 2 * 5. This means that both x and y have 2 and 5 factors in common. But from this, you cannot find the value xy.
Insufficient.
B. 180 = 2*2*3*3*5 = 2^2 * 3^2 * 5. LCM is the union of both x and y (LCM and GCD are Just like set theory concept-venn diagram)
Again, you cannot find out xy with just LCM information. Insufficient.

Combined,
There is a very important rule to remember. It's worth memorizing.
"If X and Y are integers, X * Y is always equal to LCM(X,Y) * GCD(X,Y)"

We know LCM and GCD of x and y from statements A and B. Therefore, x*y can be found. Sufficient.
Hence C.


5. x + y = 77

B. Lets say you have these options - (1s,1t), (2s,2t), (3s,3t), (4s,4t).. It cannot be (1s,1t), (2s,2t), and (4s,4t) because it cannot add to 77. Only option left is (3s,3t). Now, only 38 and 39 add to 77. So its sufficient.
Hence it's D.

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by gmattic » Sun Jan 03, 2010 9:14 pm
5. x + y = 77

B. Lets say you have these options - (1s,1t), (2s,2t), (3s,3t), (4s,4t).. It cannot be (1s,1t), (2s,2t), and (4s,4t) because it cannot add to 77. Only option left is (3s,3t). Now, only 38 and 39 add to 77. So its sufficient.
Hence it's D.
Thanks for the help.

I don't get this explanation though. Can you please re-phrase what you meant?

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by papgust » Mon Jan 04, 2010 6:38 pm
5. x + y = 77

x and y are both double digits from statement II. It varies only with unit's digit.
Assume s as x's unit digit and t as y's unit digit.

Possible combinations of x and y could start from (1s,1t) to (4s,4t).

(1s, 1t) can be ruled out since it does not add upto 77. Take the maximum value of s and t. (19, 19) ==> This will only add upto 38. So eliminate.

Same logic goes for (2s,2t).

(4s,4t) can also be ruled out. Take minimum possible values of s and r. (40, 40) ==> This goes beyond 77 i.e. 80. So, Eliminate.

Only pair left is (3s, 3t). Either it could be (38, 39) or (39, 38). But question asks only for value of xy. Both pairs provide same value of xy. So, statement II is sufficient.