arifaisal wrote:In the figure below, if AC=12, DC=18, and DB=15, what is the length of AF?
A)8
B)9
C)10
D)11
E)12
Any side of a triangle can be deemed the base.
Each base has a corresponding height.
No matter which base and height are used, the area of the triangle must be the same value.
Thus, regardless of which side of a triangle is deemed the base, bh must always yield the same product.
In triangle ADC:
If AC is deemed the base, then BD is the corresponding height.
If CD is deemed the base, then AF is the corresponding height.
Since bh must yield the same product no matter which base and height are used, we get:
(AC)(BD) = (CD)(AF)
12*15 = 18(AF)
AF = 10.
The correct answer is
C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at
[email protected].
Student Review #1
Student Review #2
Student Review #3
