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sapuna
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Question : Is k.k + k - 2 > 0 ?
1) k < 1
2) k > -1
The usual 5 answers .
Here is what I did:
k.k + k - 2 > 0 ?
(k+2)(k-1) > 0 ?
1) isnt enough because k-1 will always be negative but k+ 2 can be negative , but it can be positive os we don`t know whether k.k + k - 2 > 0 is >0 or < 0
2) since k > - 1 k + 2 and k - 1 will both always be positive so k.k + k - 2 > 0 .So I thought 2 alone is enough,
However,the correct answer is given as C - both statements are needed.
Any thoughts ?
1) k < 1
2) k > -1
The usual 5 answers .
Here is what I did:
k.k + k - 2 > 0 ?
(k+2)(k-1) > 0 ?
1) isnt enough because k-1 will always be negative but k+ 2 can be negative , but it can be positive os we don`t know whether k.k + k - 2 > 0 is >0 or < 0
2) since k > - 1 k + 2 and k - 1 will both always be positive so k.k + k - 2 > 0 .So I thought 2 alone is enough,
However,the correct answer is given as C - both statements are needed.
Any thoughts ?
