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necklace

by shashank.ism » Tue Feb 09, 2010 12:59 pm
There are "n" necklaces in a safe box (n > 1). Every necklace has the same number of diamonds. Each necklace has at least 2 diamonds. The total number of diamonds in these "n" necklaces is between 500 and 600. If this data is sufficient to find the value of n, then what can be the value of "n"?


22
23
27
29
None of these
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by anki_jain » Sat Feb 13, 2010 11:53 am
k= number of diamonds.

n*k should be between 500 and 600 for only one option.

A). 22*25= 550
B). 23*25= 575

data not sufficient.
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by vscid » Sat Feb 13, 2010 12:55 pm
anki_jain wrote:k= number of diamonds.

n*k should be between 500 and 600 for only one option.

A). 22*25= 550
B). 23*25= 575

data not sufficient.
yeah!
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by harsh.champ » Thu Feb 18, 2010 6:37 am
anki_jain wrote:k= number of diamonds.

n*k should be between 500 and 600 for only one option.

A). 22*25= 550
B). 23*25= 575

data not sufficient.
Hey anki_jain,
I wanted to ask why u have chosen 25 in both A and B.Can you highlight ur approach??

Also shashank,I think there is some typo error because the way the question is framed I think the option choices have to be among the 5 given only.

Is it the sum of 1^2 + 2^2 +3^2+......+n^2
Then we have to use the formula n(n+1)(2n+1)/6 which would be greater then 500 and less than 600.
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by ajith » Thu Feb 18, 2010 6:41 am
harsh.champ wrote:
anki_jain wrote:
Is it the sum of 1^2 + 2^2 +3^2+......+n^2
Then we have to use the formula n(n+1)(2n+1)/6 which would be greater then 500 and less than 600.
How, I may ask?

I think data is not sufficient
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by harsh.champ » Thu Feb 18, 2010 6:56 am
ajith wrote:
harsh.champ wrote:
anki_jain wrote:
Is it the sum of 1^2 + 2^2 +3^2+......+n^2
Then we have to use the formula n(n+1)(2n+1)/6 which would be greater then 500 and less than 600.
How, I may ask?

I think data is not sufficient
Well ajith,
I thought like this.
Every necklace has the same number of diamonds.
I am not sure but maybe it could mean that 2 necklace have 2 diamonds,3 necklaces have 3 diamonds and so on.
and 2+3+4+... = n
and this way we could have solved it.

Well,the framing of the ques. is a bit tricky and i guess maybe this is what the question-setter has meant to imply??

Well,I don't know and thats why I wanted people's opinion on it.
What do you think??Is my thought process wrong??
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by ajith » Thu Feb 18, 2010 7:20 am
harsh.champ wrote: Every necklace has the same number of diamonds.
I am not sure but maybe it could mean that 2 necklace have 2 diamonds,3 necklaces have 3 diamonds and so on.
and 2+3+4+... = n
and this way we could have solved it.
If I have 20 necklaces and each have 17 diamonds - I would say "Every necklace has the same number of diamonds"

The way you interpreted it is bizarre even though that may be what the question maker intended.
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