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If each of 3 digit code form integers from 1 to 20, inclusiv

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by Max@Math Revolution » Thu Jan 28, 2016 5:52 pm
If each of 3 digit code form integers from 1 to 20, inclusively, and each of the digits are different, how many possible codes are there?

A. 6,040
B. 6,840
C. 6,240
D. 6,340
E. 8,440


* A solution will be posted in two days.
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Source: — Problem Solving |

by talaangoshtari » Thu Jan 28, 2016 8:09 pm
20*19*18 = 6840 => B is the correct answer
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by Max@Math Revolution » Sun Jan 31, 2016 6:28 pm
If each of 3 digit code is formed of integers from 1 to 20, inclusively, and each of the digits are different, how many possible codes are there?

A. 6,040
B. 6,840
C. 6,240
D. 6,340
E. 8,440


* A solution will be posted in two days.
Join the discussion

by Brent@GMATPrepNow » Sun Jan 31, 2016 11:00 pm
Max@Math Revolution wrote:If each of 3 digit code form integers from 1 to 20, inclusively, and each of the digits are different, how many possible codes are there?

A. 6,040
B. 6,840
C. 6,240
D. 6,340
E. 8,440


* A solution will be posted in two days.
Are you sure you mean "digit"?

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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