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by PussInBoots » Tue Oct 07, 2008 6:20 am
x^x = (10^100)^(10^100) = [ (10^100)^10 ] ^ 100

On paper it would looks something like that:
...........100
........10
...100
10

Since (a^b)^c = a^(b*c) we get: x^x = 10^(100*10*100), therefore k = 100,000

Edit: Answer is wrong, a^(b^c) != (a^b)^c
Last edited by PussInBoots on Tue Oct 07, 2008 6:57 am, edited 1 time in total.
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by ska7945 » Tue Oct 07, 2008 6:41 am
k=10^102

can someone elavorate?
let's beat GMAT.
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by PussInBoots » Tue Oct 07, 2008 6:49 am
nvm
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by krazy800 » Tue Oct 07, 2008 6:50 am
sure

First X = 10^100

X^X = (10^100)^(10^100)
= (10^(10^2))^(10^100)

using the formula (a^m)^n = a^(m*n)

we get X^X = (10^((10^2)*10^100))

further simplifying the exponent ((a^m)*(a^n))= (a^(m+n)) we get X^X=10^(10^102)


Equating it to 10^K we get k = 10^102
Aiming High
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