Mo2men wrote:Is a>|b|?
(1) 2^(a−b)>16
(2) |a-b|<b
Source:e-gmat
(1) a - b must be greater than 4. If a & b are both positive, then a must be greater than b (and so a>|b|). If a & b are both negative, then |b| > a. Insufficient.
(2) Not sufficient. |a-b| < b. Picking values -- A could be 3 and b 2, in which case 1<2; or A could be 2 and b 3, in which case 1<2. In case (1), a>|b|, while in case (2) a<|b|. Note importantly, since |a-b| must be greater than or equal to 0, this implies b must be greater than or equal to 0.
(1) & (2) combined: B must be greater than or equal to zero, and a-b>4. Thus, a>b+4. Since b must be greater than or equal to zero, |b|=b. It follows that, since a>b+4, a>b and a>|b|.
Therefore, it would appear the answer is
C.
800 or bust!