Statement 1: AC & BD are perpendicular bisectoryellowho wrote:Is quadrilateral ABCD= rhombus?
1) AC & BD are perpendicular bisector
2) ABCD = square
Hence, ABCD is a kite, which may or may not be a rhombus.
Not sufficient
Statement 2: ABCD is a square
All squares are rhombuses.
Therefore, ABCD is a rhombus.
Sufficient
The correct answer is B.

















