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Which of the following leads to the correct mathematical solution for the number of ways that the letters of the word BANANA could be arranged to create a six-letter code?
A. 6!
B. 6! - (3! + 2!)
C. 6! - (3! x 2!)
D. 6! / (3! + 2!)
E. 6! / (3! x 2!)
The OA is E.
Please, can someone explain why this is a combinatorics problem instead of a permutation? I know permutation is concerned with order and combinatorics is not. When we rearranged letters in a word, aren't we concerned with the order of the letters?
A. 6!
B. 6! - (3! + 2!)
C. 6! - (3! x 2!)
D. 6! / (3! + 2!)
E. 6! / (3! x 2!)
The OA is E.
Please, can someone explain why this is a combinatorics problem instead of a permutation? I know permutation is concerned with order and combinatorics is not. When we rearranged letters in a word, aren't we concerned with the order of the letters?
