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by grandh01 » Thu Aug 09, 2012 2:11 pm
Marion rented a car for $18.00 plus $0.10 per mile driven. Craig rented a car for $25.00 plus $0.05 per mile driven. If each drove d miles and each was charged exactly the same amount for the rental, then d equals
(A) 100 (B) 120 (C) 135
(D) 140 (E) 150
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by theCEO » Thu Aug 09, 2012 2:24 pm
[spoiler](d)[/spoiler]

18 + 0.1d = 25 + 0.05d
0.05d = 7
d = 7/0.05 = 140
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by Jeff@TargetTestPrep » Thu Dec 14, 2017 4:48 pm
grandh01 wrote:Marion rented a car for $18.00 plus $0.10 per mile driven. Craig rented a car for $25.00 plus $0.05 per mile driven. If each drove d miles and each was charged exactly the same amount for the rental, then d equals
(A) 100 (B) 120 (C) 135
(D) 140 (E) 150
We can create the following equation:

18 + 0.1d = 25 + 0.05d

0.05d = 7

d = 7/0.05 = 140

Answer: D

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