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by krishnasty » Mon Aug 01, 2011 12:49 am
IMO C
(R^c)(R^d)(R^e) = R^-12
= R^(c+d+e) = R^-12
= c+d+e = -12

If we have to make all the digits as different and keep c shortest, the best possible combination is c=-9, d = -1, e= -2

Hence, C = -9
Last edited by krishnasty on Mon Aug 01, 2011 12:57 am, edited 1 time in total.
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by naveen451 » Mon Aug 01, 2011 12:50 am
IMO B
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by MBA.Aspirant » Mon Aug 01, 2011 6:56 am
I think it should be C

If R = 1 and the smallest c is -12, the other 2 will be raised to 0 which aren't -ve and not different

if c = -10, other 2 = -1, same scenario

if c= -9, a = -1, b = -2, and R^-12
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