A:
It is an AP with assumed first player wt a and diff d
w13 = a+12d
w5 = a+4d
(w13+w5)*(w13-w5) = (2a+16d)(8d) = 16d(a+8d)=244
=>4d(a+8d) = 61
61 is a prime no, since wt are natural no, a ad d all will be prime so multiplication of two natural no cant be prime
check if 244 is correct? It should be some different no? Otherwise the question stem will be correct. Assuming it to be 240
d(a+8d) = 15 it will have d as 1, a as 7, there is no other possibility as 15 has two factors and 5 so the pairs will be(1, 15), (3,5) ,(5,3), (15,1)
3 and 5 cant be there as weight cant be negative and 8 is bigger than 5 so the only factors will be 1, 15
so the sequence will be: 7, 8 , 9 , 10, ..., 23
total et= 17/2(7+23) = 15*17
B: Doesnt tell anything
C: assuming the data is something other than 240 in case it has two possible factors satisying a/d and above eqn C can be an ane...
Charged up again to beat the beast
