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by maihuna » Tue Mar 15, 2011 12:14 pm
In the xy-plane, at what point does the graph of y = (x + k)^2
intersect the x-axis?
(1) The graph includes the point (1; 9).
(2) The graph includes the point (-1; 1).
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by Night reader » Tue Mar 15, 2011 1:06 pm
The question asking about intercept of x when y=0, so we to find k ...
st(1) (1;9) and y=(x+k)^2 --> there are two values of k when y will be turned into 1; k E {-4;2} 9=(1+k)^2 <> |3|=1+k Not Sufficient;
st(2) (-1;1) the same explanation as for st(1) applies here --> |1|=-1+k, k E {0;2} Not Sufficient;
Combined st(1&2): only k=2 applies Sufficient, as we can find coordinate of y from the line equation y=(x+2)^2

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maihuna wrote:In the xy-plane, at what point does the graph of y = (x + k)^2
intersect the x-axis?
(1) The graph includes the point (1; 9).
(2) The graph includes the point (-1; 1).
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by clock60 » Tue Mar 15, 2011 1:37 pm
agree with Reader my answer Cwe need to find fixed value of k
(1) from 1 st k=2, k=-4
(2) from 2 st k=2, k=0
from both k=2, and x=-2

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by force5 » Tue Mar 15, 2011 2:36 pm
C it is....