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Work Problem

by finance » Thu Jun 30, 2011 6:48 am
It takes 6 beavers 10 hours to build a certain dam, working at a uniform rate. If six beavers start to build the same dam at noon, and one beaver per hour is added beginning at 6:00 PM, at what time will the dam be complete?

A) 7:40 PM
B) 8:00 PM
C) 8:20 PM
D) 8:40 PM
E) 9:00 PM
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by amit2k9 » Thu Jun 30, 2011 7:24 am
total man hours required = 6*10 = 60

man hours done till 6 pm = 6*6 = 36

between 6-7 man hours = 7
between 7-8 man hours = 8
between 8-9 man hours = 9

thus total = 36 + 7+8+9 = 60.

hence E.
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by winniethepooh » Thu Jun 30, 2011 7:35 am
6B - 10 hrs = 60 hrs.
Noon(12) to 6 PM = 6B x 6hrs = 36 hrs.
Added 1 B hr = (6 x 1)+1= 7 hrs(36+7 = 43)
Added another B hr = (6 x 1)+2 = 8hrs(43+8 = 51)
Add another B hr = (6 x 1)+ 3 = 9 Hrs(51+9 = 60

Hence, 6 PM + 3 hrs = 9PM
Hence, E.
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