Three quarts of a bleaching chemical, Minum, contains 5 percent hydrogen peroxide and water. A different type of bleaching chemical, Maxim, which contains 20 percent hydrogen peroxide, will be mixed with the three quarts of Minum. How much of type Maxim should be added to the three quarts of Minum so that the resulting mixture contains 15 percent hydrogen peroxide?
A. 3 quarts
B. 3.75 quarts
C. 4.5 quarts
D. 6 quarts
E. 9 quarts
Can anyone explain me the procedure. thank you.
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sudhir3127
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My Answer is 6
Here it goes...
3 qts Minum contains 5% hydrogen peroxide = 3*5/100 = 0.15 quarts
Water = 3-0.15 = 2.85 quarts
Let the quantity of Maxim be X,
x qts of maxim contains 20 percent hydrogen peroxide
= X* 20/100= 0.2X
Water = X - 0.2X= 0.8X
Total Mixture = 3+X
hydrogen peroxide = 0.2X+ 0.15
in the mixture hydrogen peroxide is 15% of the total amount
(0.20x+0.15) = 15*(3+x)/100
20x + 15 = 45 + 15x
5x = 30
x=6
Please let me know if have doubts ...
Here it goes...
3 qts Minum contains 5% hydrogen peroxide = 3*5/100 = 0.15 quarts
Water = 3-0.15 = 2.85 quarts
Let the quantity of Maxim be X,
x qts of maxim contains 20 percent hydrogen peroxide
= X* 20/100= 0.2X
Water = X - 0.2X= 0.8X
Total Mixture = 3+X
hydrogen peroxide = 0.2X+ 0.15
in the mixture hydrogen peroxide is 15% of the total amount
(0.20x+0.15) = 15*(3+x)/100
20x + 15 = 45 + 15x
5x = 30
x=6
Please let me know if have doubts ...
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parallel_chase
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original Qty=3
Hydrogen = 5% of 3
added Qty=x
hydrogen=20%x
new formed Qty=x+3
hydrogen=15%(x+3)
equation:
5%of3+20%x = 15%(x+3)
solve for x
X=6
Hence D
Hydrogen = 5% of 3
added Qty=x
hydrogen=20%x
new formed Qty=x+3
hydrogen=15%(x+3)
equation:
5%of3+20%x = 15%(x+3)
solve for x
X=6
Hence D
I think a good way to look at this problem is the following.
part/whole = percentage (everyone knows this)
We can see that Maxim will be our variable.
PART
3 Quarts Minum + Maxim
3(.005) + 0.20X
Whole
How many quarts of Maxim added to 3 quarts Minum
X + 3
part/whole = .15
3(.005) + 0.20X
______________ = .15
X + 3
Solving for X as everyone else did you will get 6 but I think its easier to see if you can look at it as a simple percentage problem.
part/whole = percentage (everyone knows this)
We can see that Maxim will be our variable.
PART
3 Quarts Minum + Maxim
3(.005) + 0.20X
Whole
How many quarts of Maxim added to 3 quarts Minum
X + 3
part/whole = .15
3(.005) + 0.20X
______________ = .15
X + 3
Solving for X as everyone else did you will get 6 but I think its easier to see if you can look at it as a simple percentage problem.
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neelgandham
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Here it goes !Viren1808 wrote:Can anyone please help me to solve this question via Aligation method??
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GMATGuruNY
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Another approach would be to plug in the answers.warlock wrote:Three quarts of a bleaching chemical, Minum, contains 5 percent hydrogen peroxide and water. A different type of bleaching chemical, Maxim, which contains 20 percent hydrogen peroxide, will be mixed with the three quarts of Minum. How much of type Maxim should be added to the three quarts of Minum so that the resulting mixture contains 15 percent hydrogen peroxide?
A. 3 quarts
B. 3.75 quarts
C. 4.5 quarts
D. 6 quarts
E. 9 quarts
Can anyone explain me the procedure. thank you.
Since the percentage in the mixture (15%) is closer to the percentage in Maxim (20%), the mixture must be more than 1/2 Maxim.
Eliminate A.
Of the remaining answer choices, we should start with the next greatest that is an integer.
Amount of hydrogen peroxide in Minum = .05(3) = .15.
Answer choice D: 6 quarts Maxim.
Amount of hydrogen peroxide in Maxim = .2(6) = 1.2 .
Total hydrogen peroxide/Total mixture = (.15+1.2)/(3+6) = 1.35/9 = 135/900 = 15/100 = 15%.
Success!
The correct answer is D.
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Scott@TargetTestPrep
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We can let the number of quarts of Maxim = y and create the following equations:warlock wrote:Three quarts of a bleaching chemical, Minum, contains 5 percent hydrogen peroxide and water. A different type of bleaching chemical, Maxim, which contains 20 percent hydrogen peroxide, will be mixed with the three quarts of Minum. How much of type Maxim should be added to the three quarts of Minum so that the resulting mixture contains 15 percent hydrogen peroxide?
A. 3 quarts
B. 3.75 quarts
C. 4.5 quarts
D. 6 quarts
E. 9 quarts
0.05(3) + 0.2y = 0.15(3 + y)
5(3) + 20y = 15(3 + y)
15 + 20y = 45 + 15y
5y = 30
y = 6
Answer: D
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