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silverflamein
- Junior | Next Rank: 30 Posts
- Posts: 23
- Joined: Wed Oct 19, 2011 7:12 pm
Let:
A=fraction of mixture that is A
B=fraction of mixture that is B
C=fraction of mixture that is C
A,B, and C are the only kinds of coffee we want in the mixture, so it must be that A+B+C=1.
Statement 1. A=2C. Obviously insufficient as it tells us nothing about the cost.
Statement 2. With these prices, we can set up the following equation: 4A+10B+6C=8----dividing by 2----->2A+5B+3C=4. With A+B+C=1, we now have two equations and three variables. This is not enough information to solve for unique values of A,B, and C. For example, A=1/5, B=3/5, C=1/5 would be a solution as would A=1/4, B=1/8, C=5/8. INSUFFICIENT.
Statements 1&2: Adding A=2C to the two equations we got from statement 2 gives us three equations with three variables. Plugging A=2C into both equations yields:
5B+7C=4
B+3C=1
Solving this system gives us: B=5/8 C=1/8, which means A=1/4.
Hence the ratio A:B:C=2:5:1
Ans: C
Of course, you shouldn't necessarily solve it all the way out once you realize there is a unique solution.
