Hence eliminate D. The total value of the product has to be more
than 24000 since the most significant digits of the numbers are
4 and 6. Hence eliminate A and B. That leaves us with C and E.
To have 6 in the units place of the result, we can have 2 and 7,
while to have 8 we can have 1 or 6 in the units place of 6b. If
you divide E with 61 or 66 most significant digit will be 5 and
hence E can not be the answer.
HTH
bobdylan wrote:If 4a8 and 6b are integers with unspecified digits a and b, which of the following could be the result of multiplying 4a8 X 6b?
a. 20,574
b23,816
c.30,686
d. 32,507
e. 36,728
