RTD explanation required

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RTD explanation required

by karthikpandian19 » Thu May 10, 2012 5:36 pm
A and B ran a race of 480 m. In the first heat, A gives B a head start of 48 m and beats him by 1/10 th of a minute. In the second heat, A gives B a head start of 144 m and is beaten by 1/30 th of a minute. What is B's speed in m/s?

(A) 12

(B) 14

(C) 16

(D) 18

(E) 20
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by GMATGuruNY » Thu May 10, 2012 7:00 pm
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by karthikpandian19 » Thu May 10, 2012 8:45 pm
The link is illustrated with the PLUGGING NOS and SKIMMING concept.

Is their a straight forward way of solving this problem???
GMATGuruNY wrote:I posted a solution here:

https://www.beatthegmat.com/difficult-ma ... -t429.html

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by aneesh.kg » Thu May 10, 2012 9:27 pm
Let the speed of A be A m/s, and the speed of B be B m/s.

In the first case,
tA = tB - 6

480/A = 0.9*480/B - 6 --(1)
(Since 48 is 10% of total distance)

In the second case,
tB = tA - 2
(Since 144 is 30% of total distance)
0.7*480/B = 480/A - 2 ---(2)

From, the two equations,
0.9*480/B - 6 = 0.7*480/B + 2
0.2*480/B = 8

B = 12

[spoiler](A)[/spoiler] is the answer
Last edited by aneesh.kg on Thu May 10, 2012 9:30 pm, edited 2 times in total.
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by GMATGuruNY » Thu May 10, 2012 9:29 pm
karthikpandian19 wrote:A and B ran a race of 480 m. In the first heat, A gives B a head start of 48 m and beats him by 1/10 th of a minute. In the second heat, A gives B a head start of 144 m and is beaten by 1/30 th of a minute. What is B's speed in m/s?

(A) 12

(B) 14

(C) 16

(D) 18

(E) 20
Let A = A's rate and B = B's rate.

A gives B a head start of 48 meters:
After the head start, the distance traveled by B = 480-48 = 432 meters.
A travels the entire distance.
Time for A to travel 480 meters = 480/A.
Time for B to travel 432 meters = 432/B.
A wins by 1/10 of a minute = 6 seconds.
In other words, the difference between B's time and A's time is 6 seconds:
432/B - 480/A = 6.

A gives B a head start of 144 meters:
After the head start, the distance traveled by B = 480-144 = 336 meters.
A travels the entire distance.
Time for A to travel 480 meters = 480/A.
Time for B to travel 336 meters = 336/B.
B wins by 1/30 of a minute = 2 seconds.
In other words, the difference between A's time and B's time is 2 seconds:
480/A - 336/B = 2.

Adding the two equations, we get:
(432/B - 480/A) + (480/A - 336/B) = 6+2
96/B = 8
B = 12.

The correct answer is A.
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