Hi - Can someone please help in understanding the strategy to be used to solve the inequalities question mentioned below. I think i did reach the correct answer but i'm not sure if i am solving it correctly.
Question =>
If 3 < |x-5| < 7 , where x is an integer, how many possible values does x have?
A) 3
B) 4
C) 5
D) 6
E) 7
How did i solve:
Step 1: Assuming the modulus will result in +ve value :
3 < x-5 <7
8 < x < 12
Possible values = 9,10,11 , i.e. 3 different values..........(A)
Step 2: Assuming the modulus will result in -ve value :
3 < -(x-5) < 7
3 < -x+5 < 7
solving , 3-5 < -x+5-5 < 7-5
to be finally , -2 < x < 2
Possible values = -1,0,1 , i.e. 3 different values..........(B)
From (A) and (B)
Total 6 different possible values,
Answer = D
Kindly suggest if you think something is wrong above.
Thanks in advance.
Question =>
If 3 < |x-5| < 7 , where x is an integer, how many possible values does x have?
A) 3
B) 4
C) 5
D) 6
E) 7
How did i solve:
Step 1: Assuming the modulus will result in +ve value :
3 < x-5 <7
8 < x < 12
Possible values = 9,10,11 , i.e. 3 different values..........(A)
Step 2: Assuming the modulus will result in -ve value :
3 < -(x-5) < 7
3 < -x+5 < 7
solving , 3-5 < -x+5-5 < 7-5
to be finally , -2 < x < 2
Possible values = -1,0,1 , i.e. 3 different values..........(B)
From (A) and (B)
Total 6 different possible values,
Answer = D
Kindly suggest if you think something is wrong above.
Thanks in advance.

















