{a^2 (b-c) + b^2 (c-a) + c^2 (a-b) } / {abc} is the same as.
a. (a^2 + b^2 + c^2)(a+b+c)
b. (a + b)(b+c)(c+a)
c. (a-b)(c-a)
d. (a-b) / c + (b-c) / a + (c-a) / b
e. b/a + c/b + a/c
Please help to solve this problem.
a. (a^2 + b^2 + c^2)(a+b+c)
b. (a + b)(b+c)(c+a)
c. (a-b)(c-a)
d. (a-b) / c + (b-c) / a + (c-a) / b
e. b/a + c/b + a/c
Please help to solve this problem.
Govind
