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govind_raj_76
- Senior | Next Rank: 100 Posts
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D is the answer.govind_raj_76 wrote:{a^2 (b-c) + b^2 (c-a) + c^2 (a-b) } / {abc} is the same as.
a. (a^2 + b^2 + c^2)(a+b+c)
b. (a + b)(b+c)(c+a)
c. (a-b)(c-a)
d. (a-b) / c + (b-c) / a + (c-a) / b
e. b/a + c/b + a/c
Please help to solve this problem.
multiply the terms and take out common you get
ab(a-b)+bc(c-a)+ac(c-a)/abc
now split all ab(a-b)/abc = a-b/c
now split a^2(b-c)/abc =
