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Senior | Next Rank: 100 Posts
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by StoneBlack » Tue Jul 05, 2011 2:21 am
There are 150 students at Seward High School. 66 students play baseball, 45 play basketball, and 42 play soccer. 27 students play exactly two sports, and three students play all three of the sports. How many of the 150 students play none of the three sports?
A) 0
B) 27
C) 30
D) 99
E) 78

Do we get B as the OA?
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by finance » Tue Jul 05, 2011 2:42 am
it's C.

Let the number of students who play both baseball and soccer be a.
basketball and baseball be b.
basketball and soccer be c.
a+b+c= 27

We can express the number of students who play as:

66+(45-3)-b-c+(42-3)-a-c+c= 66+42+39-b-c-a=147-(a+b+c)
whic equals 147-27=120

so 120 students play, therefore 150-120=30 students play none of the games.
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by StoneBlack » Tue Jul 05, 2011 3:21 am
Yes. Agree. Answer is C. 30 players.
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by worldpeace93 » Tue Jul 05, 2011 4:15 am
answer is C.
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by Jeff@TargetTestPrep » Tue Dec 19, 2017 7:17 am
StoneBlack wrote:There are 150 students at Seward High School. 66 students play baseball, 45 play basketball, and 42 play soccer. 27 students play exactly two sports, and three students play all three of the sports. How many of the 150 students play none of the three sports?
A) 0
B) 27
C) 30
D) 99
E) 78
We can create the following equation:

Total students = # who play baseball + # who play basketball + # who play soccer - # who play exactly two - 2(# who play all 3) + # who play neither

150 = 66 + 45 + 42 - 27 - 2(3) + n

150 = 120 + n

n = 30

Answer: C

Jeffrey Miller
Head of GMAT Instruction
[email protected]

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