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by j_shreyans » Tue May 05, 2015 8:24 am
A store sells a certain product at a fixed price per unit. At the product's current price, q units cost a total of exactly $300. If the price were lowered by $5 from its current value, then q + 2n units would cost exactly $300; if the price were raised by $5, then q - n units would cost exactly $300. What is the value of q?

A)10
B)15
C)20
D)25
E)30

Guys ,

Can you please solve this by algebraic approach , i couldn't succeed .

Thanks ,

Shreyans
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Source: — Problem Solving |

by GMATGuruNY » Tue May 05, 2015 8:31 am
j_shreyans wrote:A store sells a certain product at a fixed price per unit. At the product's current price, q units cost a total of exactly $300. If the price were lowered by $5 from its current value, then q + 2n units would cost exactly $300; if the price were raised by $5, then q - n units would cost exactly $300. What is the value of q?

A)10
B)15
C)20
D)25
E)30
We need 3 prices spaced $5 apart that divide evenly into 300.
Make a list of options:
5, 10, 15, 20, 25, 30...

The prices above imply that the following numbers of units can be purchased:
300/5 = 60.
300/10 = 30.
300/15 = 20.
300/20 = 15.

300/25 = 12.
300/30 = 10.

According to the problem, the numbers of units that can be purchased are -- in ascending order -- q-n, q, and q+2n.
The difference between the greatest number and the median number (2n) is TWICE the difference between the median number and the least number (n).
Only the values in red satisfy this constraint:
30-20 = 10.
20-15 = 5.

Thus, the value of q -- the median number of units that can be purchased -- is 20.

The correct answer is C.
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by prachi18oct » Wed May 06, 2015 8:44 am
We can PLUG in answers also.
1. qp = 300
2.(q-n )* (p+5) = 300
3. (q+2n)* (p-5) = 300

Starting from middle option q = 20

P = 300/20 = 15

now validating 2 & 3

20-n * p+5 = 300
20 - n = 15 = > n = 5

Check in 3.=> (20 + 2*5 ) * (15-5) = 30 * 10 = 300 BINGO!
OA C.
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