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A line is graphed on a coordinate plane. How many times less is the distance between the \(y\)-intercept and the \(x\)

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A line is graphed on a coordinate plane. How many times less is the distance between the \(y\)-intercept and the \(x\)

by VJesus12 » Thu Sep 03, 2020 6:30 am

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A line is graphed on a coordinate plane. How many times less is the distance between the \(y\)-intercept and the \(x\)-axis than the distance between the \(x\)-intercept and the \(y\)-axis?

(1) The slope of the line is \(-\dfrac9{13}.\)

(2) The \(y\)-intercept is located at \((0, 26).\)

Answer: C

Source: Veritas Prep
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Source: — Data Sufficiency |
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Re: A line is graphed on a coordinate plane. How many times less is the distance between the \(y\)-intercept and the \(x

by swerve » Thu Sep 03, 2020 2:08 pm

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VJesus12 wrote: ↑
Thu Sep 03, 2020 6:30 am
 A line is graphed on a coordinate plane. How many times less is the distance between the \(y\)-intercept and the \(x\)-axis than the distance between the \(x\)-intercept and the \(y\)-axis?

(1) The slope of the line is \(-\dfrac9{13}.\)

(2) The \(y\)-intercept is located at \((0, 26).\)

Answer: C

Source: Veritas Prep
To solve this problem we need the \(x\) and \(y\) intercepts. We can find these intercepts with the \(y=mx+b\) equation of the line.

So, if we can find the line's slope \(m\) and the \(y\)-intercept \(b\), we will have sufficient information.

Each of the two statements gives us one piece of the equation, so we need to take them together.

Therefore, the correct answer is C.
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