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Geisslerbg
- Newbie | Next Rank: 10 Posts
- Posts: 5
- Joined: Thu Oct 16, 2008 11:47 am
z^n =1
From 1.
n is non-zero so could be -ve or +ve int.
possibilities are 1^1, 1^2, 1^(-2), (-1)^2, (-1)^(any even int)
So z = {1, -1} Not sufficient
From 2. z > 0.
anynumber ^ 0 = 1. So any number +ve, -ve raised to 0th power is 1.
So not sufficient.
Combine 1 and 2.
We get 1^anynumber = 1. So z =1
Answer is C
HT Helps
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