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Aquarium Problem - less troublesome method to solve?

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by zachthegnome » Thu Jan 06, 2011 5:04 am
There must be a way to do this one without all of the math. Please let me know if any of you guys see it.

A small cubical aquarium has a depth of 1 foot. In the small aquarium there is a big fish with volume 44 cubic inches. A big cubical aquarium has a depth of 2 feet and 88 fishes each with a volume of 2 cubic inches. What is the difference in the amount of water between teh two aquariums if they are both completly filled?

A) 246
B) 300
C) 11,964
D) 13,824
E) 16,348

answer is C

Thank you in advance.
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by shovan85 » Thu Jan 06, 2011 5:26 am
zachthegnome wrote:There must be a way to do this one without all of the math. Please let me know if any of you guys see it.

A small cubical aquarium has a depth of 1 foot. In the small aquarium there is a big fish with volume 44 cubic inches. A big cubical aquarium has a depth of 2 feet and 88 fishes each with a volume of 2 cubic inches. What is the difference in the amount of water between teh two aquariums if they are both completly filled?

A) 246
B) 300
C) 11,964
D) 13,824
E) 16,348

answer is C

Thank you in advance.
1 ft = 12 inch

Volume of water in first cubicle 12 * 12 * 12 - 44
Volume of water in second cubicle 24 * 24 * 24 - (2*88)

Difference = [24 * 24 * 24 - (2*88)] - [12 * 12 * 12 - 44]
= (24 * 24 * 24 - 12 * 12 * 12) - (2*88 - 44)
= 12 * 12 * 12 (8-1) - 44(4-1)
= 12096 - 132
=11964
If the problem is Easy Respect it, if the problem is tough Attack it
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