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MGMAT - Divisibility

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Source: — Problem Solving |

by sanju09 » Fri Mar 18, 2011 12:51 am
diehard_gmat wrote:If y is the smallest positive integer such that 3,150 multiplied by y is the square of an integer, then y must be

A. 2
B. 5
C. 6
D. 7
E. 14
Note that 3150 = 2 × 3 × 3 × 5 × 5 × 7, only 2 and 7 are not forming a pair, hence, to make this a perfect square the least integer required is [spoiler]2 × 7


E
[/spoiler]
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by manpsingh87 » Fri Mar 18, 2011 12:51 am
diehard_gmat wrote:If y is the smallest positive integer such that 3,150 multiplied by y is the square of an integer, then y must be

A. 2
B. 5
C. 6
D. 7
E. 14
3150= 2*5^2*3^2*7 therefore 3150y will become perfect square if y= 14 i.e. e
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