Integer
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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Note that, 2^n is a power of 2 only. Hence, any integer equal to 2^n must be a power of 2 only.dreamv wrote:For how many integers n is 2^n=n^2?
Now, n is an integer. Hence, for n^2 to be a power of 2 only n must be a power of 2. Say, n = 2^m.
Hence, 2^n = 2^(2^m) and n^2 = (2^m)^2 = 2^(2m)
Hence, 2^(2^m) = 2^(2m)
Or, 2^m = 2m
Only possible solutions for m are m = 1 and m = 2.
Hence, n = 2 and n = 4.
The correct answer is C.
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