Integer

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Integer

by dreamv » Sat Jan 14, 2012 10:11 pm
For how many integers n is 2^n=n^2?

A.None
B.One
C.Two
D.Three
E.More than three

I was able to find only n=2, please help.
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by ArunangsuSahu » Sat Jan 14, 2012 10:13 pm
think about n=4,2

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by Anurag@Gurome » Sat Jan 14, 2012 10:28 pm
dreamv wrote:For how many integers n is 2^n=n^2?
Note that, 2^n is a power of 2 only. Hence, any integer equal to 2^n must be a power of 2 only.

Now, n is an integer. Hence, for n^2 to be a power of 2 only n must be a power of 2. Say, n = 2^m.

Hence, 2^n = 2^(2^m) and n^2 = (2^m)^2 = 2^(2m)
Hence, 2^(2^m) = 2^(2m)
Or, 2^m = 2m

Only possible solutions for m are m = 1 and m = 2.
Hence, n = 2 and n = 4.

The correct answer is C.
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