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Spartacus2000
- Junior | Next Rank: 30 Posts
- Posts: 26
- Joined: Sun May 01, 2011 2:31 pm
Coordinates of point O, the origin are (0, 0)Spartacus2000 wrote:
In the attached figure, points P and Q lie on the circle with center O. what is the value of s?
(1) 1/2
(2) 1
(3) Root 2 (could not find the symbol for root)
(4) Root 3
(5) Root 2/2
Img. is attached - I hope it is displayed
Thanks.[/img]
Just realized this is in the wrong section, sorry about that.
Angle POQ = 90º, so the slope of OP * slope of OQ = -1 (the product of the slopes of two perpendicular lines is -1).
We can find the slope of OP, as we know their coordinates.
Slope of OP = (1- 0)/(-√3 - 0) = -1/√3
So, slope of OQ = √3/1 or (√3 - 0)/(1 - 0), which implies the x-coordinate of point Q is 1 or s = 1.
The correct answer is B.


















