Spartacus2000 wrote:
In the attached figure, points P and Q lie on the circle with center O. what is the value of s?
(1) 1/2
(2) 1
(3) Root 2 (could not find the symbol for root)
(4) Root 3
(5) Root 2/2
Img. is attached - I hope it is displayed
Thanks.[/img]
Just realized this is in the wrong section, sorry about that.
Coordinates of point O, the origin are (0, 0)
Angle POQ = 90º, so the slope of OP * slope of OQ = -1 (the product of the slopes of two perpendicular lines is -1).
We can find the slope of OP, as we know their coordinates.
Slope of OP = (1- 0)/(-√3 - 0) = -1/√3
So, slope of OQ = √3/1 or (√3 - 0)/(1 - 0), which implies the x-coordinate of point Q is 1 or s = 1.
The correct answer is B.
