3. If the product of the integers w,x,y, and z is 770, and if 1 < w < x < y < z, what is the value of w + z?
A. 10
B. 13
C. 16
D. 18
E. 21
A. 10
B. 13
C. 16
D. 18
E. 21
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770 = 2*5*7*11.oquiella wrote:3. If the product of the integers w,x,y, and z is 770, and if 1 < w < x < y < z, what is the value of w + z?
A. 10
B. 13
C. 16
D. 18
E. 21
GMATGuruNY wrote:770 = 2*5*7*11.oquiella wrote:3. If the product of the integers w,x,y, and z is 770, and if 1 < w < x < y < z, what is the value of w + z?
A. 10
B. 13
C. 16
D. 18
E. 21
Since wxyz = 770 and 1<w<x<y<z, w=2, x=5, y=7 and z=11.
Thus, w+z = 2+11 = 13.
The correct answer is B.
Here's a free video on how to find the prime factorization of a number: https://www.gmatprepnow.com/module/gmat- ... /video/825oquiella wrote: How Did you factor 770 so quickly?
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