EricKryk wrote:Aaron will jog from home at x miles per hour and then walk back home by the same route at y miles per hour. How many miles from home can Aaron jog so that he spends a total of t hours jogging and walking?
(A) xt/y
(B) (x+t)/(xy)
(C) (xyt)/(x+y)
(D) (x+y+t)/(xy)
(E) [(y+t)/x] - (t/y)
When the answers have variables, plug in your own numbers.
Let's say Aaron jogs at x = 5 miles/hour and walks at y = 2 miles/hour.
Now we need a distance.
In a rate problem, when the distance is undefined, plug in your own number for the distance.
Let's say the distance = 10 miles.
Time = Distance/Rate
If Aaron jogs at x= 5 miles/hour, it will take him 10/5 = 2 hours to jog the 10 miles.
If Aaron walks at y = 2 miles/hour, it will take him 10/2 = 5 hours to walk the 10 miles.
Since t is the total time spent jogging and walking, t = 2 + 5 = 7.
The question wants to know how far Aaron can jog. With our numbers, he's jogging 10 miles. Which answer choice = 10?
A. xt/y = 5(7)/2 = 17.5. Incorrect.
B. (x+t)/xy = (5+7)/(5*2) = 12/10. Incorrect.
C. (xyt)/(x+y) = (2*5*7)/(2+5) = 70/7 = 10. Success!
D. (x+y+t)/(x+y) = (2+5+7)/(2+5) = 14/7 = 2. Incorrect.
E. [(y+t)/x] - (t/y) = [(2+7)/5] - (7/2) = 9/5 - 7/2 = -17/10. Incorrect.
Since only answer choice C gave us the 10 miles we were looking for, the correct answer is
C.
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