BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

remainder

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 435
Joined: Mon Mar 15, 2010 6:15 amFollowed by: 1 member
Thanked: 32 times

by eaakbari » Thu Apr 15, 2010 6:21 am
I guess the answer is 4.

Since the question imposes that remainder will be same for all values of n. I took n as 1

that gives us 3 ^11

To find out the units place, we know

3^2 = 9
3^3 = 27
3 ^4 = 81
3 ^ 5 = _9

So we can say the units digit is a repeating pattern of 9,7,8.

Hence 11 will be 7

Now ____7 + 2 = _____9

If we divide this by 5 , by looking solely at the units digit we can say remainder is 4, as needs units digit as either 0 or 5.
Whether you think you can or can't, you're right.
- Henry Ford
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1309
Joined: Wed Mar 17, 2010 11:41 pmFollowed by: 5 members
Thanked: 33 times

by pradeepkaushal9518 » Thu Apr 15, 2010 6:55 am
imO answer is 4 what is the OA
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 208
Joined: Sun Sep 28, 2008 12:30 pm
Thanked: 22 times

by neoreaves » Thu Apr 15, 2010 9:17 am
IMO 1


3^8n --> lets figure this out

Lets take a look at the unit digits for 3^n
3^1 = 3
3^2 =9
3^3 = 7
3^4 = 1
3^5 = 3

thus we have iterations of 3971 and we can safely say that 8n is a multiple of 4 so no matter what 3^8n has unit digit of 1


Now lets add the unit digit with the rest of the expression

1+ 3 + 2 = 6

6 /5 = 1

Thus answer should be 1
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 435
Joined: Mon Mar 15, 2010 6:15 amFollowed by: 1 member
Thanked: 32 times

by eaakbari » Thu Apr 15, 2010 9:19 am
neoreaves wrote:IMO 1


3^8n --> lets figure this out

Lets take a look at the unit digits for 3^n
3^1 = 3
3^2 =9
3^3 = 7
3^4 = 1
3^5 = 3

thus we have iterations of 3971 and we can safely say that 8n is a multiple of 4 so no matter what 3^8n has unit digit of 1


Now lets add the unit digit with the rest of the expression

1+ 3 + 2 = 6

6 /5 = 1

Thus answer should be 1
Hey neoreaves
I agree your solution is correct but I think the question is 3^(8n+3) + 2 not 3^8n+3 + 2. Then again I may be wrong and you right
Whether you think you can or can't, you're right.
- Henry Ford
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 208
Joined: Sun Sep 28, 2008 12:30 pm
Thanked: 22 times

by neoreaves » Thu Apr 15, 2010 9:24 am
eaakbari wrote:
neoreaves wrote:IMO 1


3^8n --> lets figure this out

Lets take a look at the unit digits for 3^n
3^1 = 3
3^2 =9
3^3 = 7
3^4 = 1
3^5 = 3

thus we have iterations of 3971 and we can safely say that 8n is a multiple of 4 so no matter what 3^8n has unit digit of 1


Now lets add the unit digit with the rest of the expression

1+ 3 + 2 = 6

6 /5 = 1

Thus answer should be 1
Hey neoreaves
I agree your solution is correct but I think the question is 3^(8n+3) + 2 not 3^8n+3 + 2. Then again I may be wrong and you right

I think on actual gmat there wont be any ambiguity about that but for now I think we have to go by what is presented to us ....in this case--> without the parenthesis ....so thats why i solved like that ....
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 6
Joined: Sat Jan 23, 2010 8:13 am

by slortta » Thu Apr 15, 2010 1:47 pm
thanks so much... the answer is 4
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1