rakeshd347 wrote:Is x² − y² divisible by 8?
(1) x and y are even integers.
(2) x+y is divisible by 8.
Target question: Is x² − y² divisible by 8?
Statement 1: x and y are even integers.
There are several values of x and y that satisfy this condition. Here are two:
Case a: x = 4 and y = 0, in which case
x² − y² is divisible by 8
Case b: x = 4 and y = 2, in which case
x² − y² is not divisible by 8
Since we cannot answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: x+y is divisible by 8.
There are several values of x and y that satisfy this condition. Here are two:
Case a: x = 6 and y = 2, in which case
x² − y² is divisible by 8
Case b: x = 7.9 and y = 0.1, in which case
x² − y² is not divisible by 8
Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
Notice that we can take the expression in the target question,
x² − y², and factor it to get
(x+y)(x-y)
If x and y are integers, we know that (x+y) and (x-y) are both
integers.
If x+y is divisible by 8, then
(x+y)(x-y) is divisible by 8
In other words,
x² − y² is definitely divisible by 8
Since we can answer the
target question with certainty, the combined statements are SUFFICIENT
Answer =
C
Cheers,
Brent