Gprep absolute value

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Re: Gprep absolute value

by logitech » Thu Nov 06, 2008 9:38 pm
schumi_gmat wrote:y>=0, what is value of x?

1. mod(x-3) >=y
2. mod (x-3)<= -y

[spoiler]OA = B[/spoiler]
This question needs an explanation, and that explanation is what the heck the MOD function is...Engineers will not have a problem with this question but rest of the people can wonder what MOD is:

The modulus function returns positive value of a variable or an expression. For this reason, this function is also referred as absolute value function. In reference to modulus of an independent variable, the function results in a non-negative value of the variable, irrespective of whether independent variable is positive or negative. [/i]


1. mod(x-3) >=y

|x-3| >= y.
x >= y+3

INSUF








2. mod (x-3)<= -y

|x-3|<=-y => y=0 Remember the mod function is non-negati

|x-3|=0

x=3

SUFF

Hence , B


[/i]
LGTCH
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by schumi_gmat » Fri Nov 07, 2008 7:49 am
Thanks buddy

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by cramya » Fri Nov 07, 2008 2:49 pm
Any other approaches for statement II?

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by maihuna » Tue Apr 14, 2009 8:00 am
somewhere I read people will try to fool you by |x| <= 0 it can at max be 0...nothing else...

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by missrochelle » Mon Aug 09, 2010 12:43 pm
Can someone explain why you set y= 0 in statment 2? Just because absolute value is non-negative, why do you set it to zero ?

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by selango » Mon Aug 09, 2010 7:16 pm
Absolute value of any integer is non negative (ie)greater or equal to zero.

If x is an integer |x|>=0


In stmt2,

mod (x-3)<= -y and y>=0

Let say y>0 and y=2

Then mod(x-3)<=-2-->mod(x-3) can be -2 or -1

But we know that absolute value is non negative.Then the above statement is invalid.

So what is the only possible value we can assume so that mod (x-3) is non negative?

We can solve this with Zero as mod(any integer)>=0

--> mod(x-3)=0

-->x=3

Hope this clarify!!!
--Anand--

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by arora007 » Wed Aug 11, 2010 8:55 am
schumi_gmat wrote:y>=0, what is value of x?

1. mod(x-3) >=y
2. mod (x-3)<= -y

[spoiler]OA = B[/spoiler]
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