Our sum is X + Y + Z + 3 + X + Y + Z + 3 +... We can see that we have a pattern of 4 terms. WIth a total of 98 terms in the sequence, we know how many complete patterns (one set of all 4 terms) we have: 98/4 = 24 R 2. We have 24 sets of 4, and 2 extra terms (which must be X and Y). We can rewrite our equation as:klmehta03 wrote:The inifinite sequence a1,a2,a3.....an.. is such that a1=X,a2=y, a3=Z,a4=3, and an=a(n-4) (<--subscript) for n>4. what is the sum of first 98 terms of sequence?
1) x=5
2) y+Z=2
OA later
=24(X + Y + Z + 3) + X + Y
To solve, we'll need a way to fill in each variable.
Statement 1 provides X, but Y and Z are still unknown. Insufficient.
Statement 2 provides Y + Z, but X is still unknown. Insufficient.
Put together, we have values for each variable. However, the problem is that we only have Y and Z together. If we fill in our equation, we're still left with a lone Y:
24(5 + 2 + 3) + 5 + Y
Y could have many values. It could be 1 if Z is 1, 0 if Z is 2, 2 if Z is 0, etc. Thus, we could end up with many different sums, so the correct answer is E
