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If there are two unique solutions to the equation x^2 + bx + 9 = 0, which of the following could not be a value of b?

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by BTGmoderatorDC » Tue Sep 08, 2020 5:20 pm

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If there are two unique solutions to the equation x^2 + bx + 9 = 0, which of the following could not be a value of b?

A. -10
B. -6.5
C. -6
D. 6.5
E. 10


OA C

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Re: If there are two unique solutions to the equation x^2 + bx + 9 = 0, which of the following could not be a value of b

by Scott@TargetTestPrep » Fri Sep 11, 2020 1:09 pm
BTGmoderatorDC wrote: ↑
Tue Sep 08, 2020 5:20 pm
 If there are two unique solutions to the equation x^2 + bx + 9 = 0, which of the following could not be a value of b?

A. -10
B. -6.5
C. -6
D. 6.5
E. 10


OA C

Solution:

Looking at our answer choices, we see that b cannot be -6. If b were -6 we would have:



x^2 - 6x + 9 = 0

(x - 3)(x - 3) = 0
x - 3 = 0 → x = 3

As we can see, if b = -6, there would be only one unique solution. However, since there must be two unique solutions, -6 can’t be a possible value for b.

Answer: C

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