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problem on average

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problem on average

by madhushree » Fri Dec 09, 2011 6:27 pm
The average of 50 numbers is 38. If two numbers 45 and 55 are discarded, the average of the remaining set of numbers is:

a.88.5

b.36

c.37

d.36.5

e. 37.5


please can u solve this

source: jumbo tests
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by adamz » Fri Dec 09, 2011 10:57 pm
The average of 50 numbers is 38. This means total of 50 numbers is 1900 (i.e 50*38)

If two numbers 45 and 55 are discarded=> New total = (1900-(55+45))=1800

So new average= 1800/48 (48 because two numbers discarded)

New Average=37.5
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