BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Factoring

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 158
Joined: Mon Nov 02, 2009 5:49 pm
Thanked: 2 times
Followed by:3 members

Factoring

by tonebeeze » Tue Apr 12, 2011 12:10 pm
Can someone walk me through the factoring process in statement 1. Please see attachment for Question.

OA =A
Attachments
Screen shot 2011-04-12 at 1.07.19 PM.png
Top
Source: — Data Sufficiency |
Legendary Member
Posts: 759
Joined: Mon Apr 26, 2010 10:15 am
Thanked: 85 times
Followed by:3 members

by clock60 » Tue Apr 12, 2011 12:48 pm
my try
4^m+4^m+4^m+4^m=4*4^m=2^2*2^(2*m)=2^(2*m+2)
2^(m+2)-2^(m+1)=2^m*2^2-2^m*2=2^m*(2^2-2)=2^m*2=2^(m+1)
and now divide
2^(2*m+2)/2^(m+1)=2^(2*m+2-m-1)=2^(m+1)
and 2^(m+1)=1=2^0
m+1=0, m=-1
i hope that i did not miss any traps that are commom in exponents problems
Top
Master | Next Rank: 500 Posts
Posts: 158
Joined: Mon Nov 02, 2009 5:49 pm
Thanked: 2 times
Followed by:3 members

by tonebeeze » Tue Apr 12, 2011 1:12 pm
No...you executed the problem well. Thanks!
Top
Post new topic Post Reply
• Page 1 of 1