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even number painted on it

by sanju09 » Wed Apr 08, 2009 5:05 am
Each of the 25 balls in a certain box is either red, blue, or white and has a number from 1 to 10 painted on it. If one ball is to be selected at random from the box, what is the probability that the ball selected will either be white or have an even number painted on it?

(1) The probability that the ball will both be white and have an even number painted on it is 0.

(2) The probability that the ball will be white minus the probability that have an eve number painted on it is 0.2.



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by mike22629 » Wed Apr 08, 2009 10:49 am
Either or Probability = p(a) + p(b) - p(a and b)

Statement I: they give you p(a and b) = 0
Know nothing about either one individually, insufficient

Statement II: they give you p(a) - p(b) = .2
Its only the difference thus, they could change.
Insuffient.

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by cubicle_bound_misfit » Wed Apr 08, 2009 2:10 pm
only one addition

p(a and b) is not equal to p(a) * p(b) as the events are not independent.

Therefore combining both statements will not help to find p(a) + p(b)
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