If the q says: x is not equal to 0
is mod(x)<1 ?

1)x^2<1
2)mod(x)<1/x



From 1 : x^2<1> +0r- (x)<1 which is mod(x)<1 here x being a factor.So sufficient.

From 2: mod(x)<1>+or-(x)<1/x (x is a factor here) but with -x being a factor would contradict the value.For example let x =1/2
so 1/2<1>1/2<2; but is -1/2 < 1/-(1/2) no.

However we are asked about whether mod(x)<1 ?
and from above we knew, yes definitely.So suficient.

Ans D.

Given:If x!=0, is |x| < 1
implied questoin:
is SQRT(x^2)<1> x^2<1

1. x^2 < 1.
suff

2. |x| < 1/x.
don't know if x is poitive or negative. insuff

answer should be A

A little confusion !

About stem 2 : it says : mod(x)<1>+or-x<1>x^2<1 so sufficient (this is my understanding)

Please clarify.

Amit