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Source: — Data Sufficiency |
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by amitansu » Mon May 12, 2008 8:13 pm
Combining both equations :

1: (3r+2-s) (4r+9-s)=0
2: (4r-6-s) (3r+2-s) =0

we have one of these factors from each could be zero.

so if we take (3r+2-s)=0=>3r+2=s

and similarly (4r-6-s)=0=>4r-6=s

now 3r+2=4r-6=>r=8 ans s=26 so we can say the values of r ans are satisfying the equation y=3x+2 (here x is r and y is s)

Any better way of solution could be much appreciated !
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